Answer:
2500 kb
Explanation:
Here, we are to calculate the bandwidth delay product
From the question, we are given that
band width = 500 Mbps
The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3
= 2500 Kbits
You may do all of the given options.
Thank You!
A range check is often used when a person works with data consisting of numbers, dates and times, or currency, ensuring that a number is within a specific range.
Explanation:
- Range checks allow a person to set suitable boundaries.
- An example of a range check is checking to see if the value of a 16-bit integer is within the capacity of a 16-bit integer. When a range check is performed, upper and lower boundaries are specified.
- Range check is a validation check which can be applied to numeric fields. This is done to ensure that only numbers within a certain domain can be entered into a field. Remember that this does not necessarily mean that the data entered will be correct. But it will certainly lie within reasonable limits.
- A method of validation which checks that data falls between an upper and lower acceptable value.
- This validation check which can be applied to numeric fields. This is done to ensure that only numbers within a certain domain can be entered into a field. Remember that this does not necessarily mean that the data entered will be correct. But it will certainly lie within reasonable limits.
Answer:
Due to unreachable DHCP server
Explanation:
As we know that Dynamic Host Configuration Protocol, in short DHCP is the network protocol which is used to central and automatic management of IP address with in the network.
So due to unreachable DHCP server a student could not able to connect with the internet.When the network connection break it means that DHCP server is offline.
So the answer is Due to unreachable DHCP server .
<u>Explanation:</u>
Hey there! you need not to panic about it ,your program didn't have Driver program i.e main program! the correct & working code is given below:
// C++ program to count even digits in a given number .
#include <iostream>
using namespace std;
// Function to count digits
int countEven(int n)
{
int even_count = 0;
while (n > 0)
{
int rem = n % 10;
if (rem % 2 == 0)
even_count++;
n = n / 10;
}
cout << "Even count : "
<< even_count;
if (even_count % 2 == 0 )
return 1;
else
return 0;
}
// Driver Code
int main()
{
int n;
std::cin >>n;
int t = countEven(n);
return 0;
}
