Answer:
Use the NIST standards!
Explanation:
- A larger key size helps, but it depends what the underlying algorithm is, so this is not in itself a solution.
- Some block ciphers are not strong.
- Hardware acceleration will only produce a result faster, not increase the strength of the encryption.
Answer:
The solution code is written in Python
- def printDottedLine():
- print(".....")
Explanation:
A function printDottedLine() is defined (Line 1). The bracket is left empty since this function is not required to take any parameters. Besides, there is no return statement inside the function as it is not expected to return anything.
Inside the function, print function is used to output a single line consisting of 5 periods as required by the question (Line 2).
Answer:
The answer is below
Explanation:
Aritifiaicla intelligence in art is an artwork created by the application of artificial intelligence software.
Some of the pros of artificial intelligence in the art are:
1. It creates a new and improved interface, specifically in graphic design such as virtual reality and 3D printing
2. It creates and mixes the artistic ideas properly, such as mixing of different instruments in music to creates a new sound
3. It establishes graphical and visual display with no blemishes o,r error when applied accordingly, such as AUTOCAD
The cons of artificial intelligence in art are:
1. Artificial Intelligence lacks emotional sense. Hence it is challenging to display artistic elements that portray genuine emotions
2. It lacks creativity. Unlike humans, artificial intelligence is not as creative as humans when it comes to words or sentence constructions in an artistic sense.
3. It doesn't apply experience to its productions. Arts can be improved with more understanding of what is happening in the society or environment; artificial intelligence cannot translate its experience into arts formation.
Answer:
int second_to_last = (number/10)%10;
int third_to_last = (number/100)%10;
Explanation:
The first expression int second_to_last = (number/10)%10; first divide the number by ten and then get modulus by dividing by ten again which will then give the second to last digit.
Assuming number is 146 the second to last digit will be 4.
for the second expression int third_to_last = (number/100)%10; first divide the number by hundred and then get modulus by dividing by ten which will then give the third to last digit.
Assuming number is 4368 the third to last digit will be 3.
