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lara31 [8.8K]
3 years ago
9

Algebra 2. I don't really understand how to find anything yet.

Mathematics
1 answer:
jeka57 [31]3 years ago
8 0
The domain is the x values we can use
range is the y values or f(x) we get from the domain
end behavior is what happens at the ends of the graph



domain seems to be all real numbers since the arrows go infinity and there aren't any discontinuities

inequality would be -∞<x<∞
set notation would be D={x|- \infty
interval notation would be (- \infty,\infty)



the range is only from 0 and up
inequality would be f(x)≥0 since it seems to approach 0, it might be f(x)>0 tho
set notation would be R={f(x)|f(x)\geq 0}
interval notation would be (0,\infty)


end behavior
as x approaches infinity, y approaches infinity
ax a approaches negative infinity, y approaches negative infinity
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antiseptic1488 [7]

Answer:

A.

Step-by-step explanation:

Q1 = 4.6

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3 years ago
Please solve the combination of equations here.
klemol [59]

Answer:

\left \{ {{x=5} \atop {y=7}} \right.

Step-by-step explanation:

\left \{ {{x+y=12} \atop {3y = 4x+1}} \right.

\left \{ {{x=12-y} \atop {3y=4x+1}} \right.

We are going to do a replacement of x for a second equation

So instead

3y=4x+1

in the place of x we are putting 12-y from the first equation, so

3y = 4(12-y)+1

To leave the brackets we need to do multiplication

3y = 4*12-4*y+1

Which is

3y = 48-4y+1

3y = -4y+49 /+4y\\7y = 49 /:7\\y = 7

How to determine x? From the first equation:

If the x +y = 12 then the x = 12-y so x = 12-7 = 5

We should write solution as a pair:

\left \{ {{x=5} \atop {y=7}} \right.

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3 years ago
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Step-by-step explanation:

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3 years ago
Number 7 and 8 plz answer quickly
Flauer [41]

(7) m∠A = 52°

(8) m∠B = 117°

Solution:

(7) Let us first define the supplementary and complementary angles.

Supplementary angles: Two angles are said to be supplementary angles if their sum is add up to 180°

Complementary angles: Two angles are said to be complementary angles if their sum is add up to 90°

Given supplement of 142° = 180° – 142°

                                           = 38°

Complement of ∠A = Supplement of 142°

⇒ Complement of ∠A = 38°

Measure of ∠A = 90° – 38°

                          = 52°

Hence m∠A = 52°.

(8) Given complement of 27° = 90° – 27°

                                                 = 63°

Supplement of ∠B = Complement of 27°

⇒ Supplement of ∠B = 63°

Measure of ∠B = 180° – 63°

                          = 117°

Hence m∠B = 117°.

3 0
4 years ago
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