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BlackZzzverrR [31]
3 years ago
13

I need.help please

Mathematics
1 answer:
dmitriy555 [2]3 years ago
6 0
Well the digit in the thousands place is about 100 times than the digit in the tens place. 
So 5,000> 50
The digit in the thousands place is more than the digit in the tens place.
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Given that g(x)=x-3/x+4 find each of the following.
maks197457 [2]

Given that the function g(x)=x-3/x+4, the evaluation gives:

  1. g(9) = 6/13.
  2. g(3) = 0.
  3. g(-4) = undefined.
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  5. g(x+h) = x+h-3/x+h+4

<h3>How to evaluate the function?</h3>

In this exercise, you're required to determine the value of the function g at different intervals. Thus, we would substitute the given value into the function and then evaluate as follows:

When g = 9, we have:

g(x)=x-3/x+4

g(9) = 9-3/9+4

g(9) = 6/13.

When g = 3, we have:

g(x)=x-3/x+4

g(3) = 3-3/3+4

g(3) = 0/13.

g(3) = 0.

When g = -4, we have:

g(x)=x-3/x+4

g(-4) = -4-3/-4+4

g(-4) = -1/0.

g(-4) = undefined.

When g = -18.75, we have:

g(x)=x-3/x+4

g(-18.75) = -18.75-3/-18.75+4

g(-18.75) = -15.75/-14.75.

g(-18.75) = 1.07.

When g = x+h, we have:

g(x)=x-3/x+4

g(x+h) = x+h-3/x+h+4

Read more on function here: brainly.com/question/17610972

#SPJ1

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Y= f(x) = a+bx
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