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Oxana [17]
3 years ago
15

Which Unit Measure would be appropriate for the volume of a cylinder that is 8 meters tall and has a radius of 4 meters?

Mathematics
2 answers:
Mashcka [7]3 years ago
8 0

The volume is always written in cubic units.

Therefore your answer is D. Cubic meters.

OLga [1]3 years ago
7 0

Answer:  Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Radius of cylinder = 4 meters

Height of cylinder = 8 meters

We need to find the volume of cylinder.

As we know the formula for "Volume of cylinder ":

Volume=\dfrac{1}{2}\pi r^2h\\\\Volume=\dfrac{1}{2}\times \dfrac{22}{7}\times 4\times 4\times 8=201.14\ m^3

As we can see that while calculating volume we consider radius two times and height one time.

So, it has 3 dimensions or units.

So, Unit measure of volume should be in cubic and both the dimensions are given in meters.

Hence, Unit measure of volume is cubic meters.

Thus, Option 'D' is correct.

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ziro4ka [17]

Answer:

-2

Step-by-step explanation:

(-3x/2) - 3 = 3

add 3 to both sides

(-3x/2) = 3

multiply both sides by 2

-3x = 6

divide both sides by -3

x= -2

5 0
2 years ago
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
How many miles are in 400 kilometers? How many miles are in 400 kilometers? Follow 3 answers 3 Report Abuse Are you sure you wan
Ivenika [448]
Hello there. :)

<span>How many miles are in 400 kilometers

248.548
</span>
7 0
2 years ago
Please dont use Actidavid links !!!!!!!!!!!!!!!!!!!
Irina-Kira [14]

Answer: okay

Step-by-step explanation:

will do

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5 0
2 years ago
It took Alice 6 5/6 hours to drive to her grandparents' house for Thanksgiving. On the way home, she ran into traffic and it too
salantis [7]

Time taken to drive to her grandparents house = 6 5/6  hours

We convert this mixed into improper fraction, we get = 41/6 hours

Time taken to drive to her grandparents house = 41/6 hours

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We convert this mixed into improper fraction, we get = 74/9 hours

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Therefore it took 1 7/18 hours longer to drive back.

6 0
3 years ago
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