Let First Sphere be the Original Sphere
its Radius be : r
We know that Surface Area of the Sphere is : 4π × (radius)²
⇒ Surface Area of the Original Sphere = 4πr²
Given : The Radius of Original Sphere is Doubled
Let the Sphere whose Radius is Doubled be New Sphere
⇒ Surface of the New Sphere = 4π × (2r)² = 4π × 4 × r²
But we know that : 4πr² is the Surface Area of Original Sphere
⇒ Surface of the New Sphere = 4 × Original Sphere
⇒ If the Radius the Sphere is Doubled, the Surface Area would be enlarged by factor : 4
The 30/60/90 right triangle is the biggest cliche in trig. We recall the sides come in ratio 
First x:
Next y:
Choice C
Answer:
x = <u>12/5</u>
Step-by-step explanation:
Since the original is 10 and the second is 6, that means that the scale is 10:6 or 5:3. It can also be related as %60 of the length.
<u>Step 1: Make an equation</u>
10/6 = 4/x
<u>Step 2: Cross Multiply</u>
10x = 24
<u>Step 3: Divide</u>
10x / 10 = 24 / 10
24/10 = 12/5
x = 2.4
I think not sure but i think the discout is $5.76
The nearst rounding to the tens is 230
