9^(3/2)*10^(2n)^(3/2)=27*10^(3n)
Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Using the Pythagorean theorem:
a^2 + b^2 = c^2
A and B are the sides and c is the hypotenuse.
4^2 + 5^2 = c^2
Simplify:
16+25 = c^2
41 = c^2
Take the square root of both sides:
c=√41
