3 years ago

What are the coordinates of the endpoints of the midsegment for △JKL that is parallel to KL¯¯¯¯¯?

2 answers:

8 0

Just took the quiz. The answer is (-1, -3) (1, -3)

Tom [10]3 years ago

6 0

The correct answer is (-1,-3) and (1,-3)

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Svetlanka [38]

Answer: I think it’s 5 I’m not sure

Step-by-step explanation:

6 0

2 years ago

Natalka [10]

If you observe that $16 = 2^4$ , you can rewrite the expression as

$16^{\frac{1}{4}} = (2^4)^{\frac{1}{4}}$

Now, if you use the exponent rule $(a^b)^c = a^{bc}$ , you may rewrite the expression again:

$(2^4)^{\frac{1}{4}} = 2^{4\cdot\frac{1}{4}} = 2^1 = 2$

6 0

3 years ago

Ratling [72]

Answer:

30a + 18b

Step-by-step explanation:

6(5a+3b)

Just multiply the six in both numbers

( 6x5a) + (6x3b)

= 30a +18b

Hope this helps =)

4 0

3 years ago

nignag [31]

-5, you never want the denominator to equal zero or else it doesnt exist!

x+5=0
x=-5

7 0

2 years ago

kirill115 [55]

Your answer is simple times 6 to 3 to get 18 then 15 by 8 to get 96 then add up everything to get 114

6 0

3 years ago