The sum of the angles of a triangle is 180º.
We have three angles:
∠yxz=3x+5
∠xzy=180º-(8x-14)
∠xyz=4x
Therefore:
(3x+5º) + [180º-(8x-14º)]+(4x)=180º
3x-8x+4x=180º-5º-14º-180º
-x=-19º
x=19º
∠yxz=3x+5º =3(19º)+5º=62º
∠xzy=180º-(8x-14)=180º-(8(19º)-14)=42º
∠xyz=4x=4(19º)=76º
Answer: m∠yxz= 62º.
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36
Answer
i think its 42.875
step-by-step explanation:
divide 343 by 8 i think
Ummm if its multiply then its 1 and 6. is its addition then its 1 and 5 or 6 and 0. if its divide it would be 6 and 1. is its subtraction then it would be 7 and 1 or 6 and 0
2/6
because after you take one quarter out you have a total of 6 left & you have 3 delaware ones and you already have 1 delaware one out of your pocket it makes it 2/6
