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2 years ago

Write the equation of the line that passes through the points (4,-6) and (-2,3)

Mathematics

1 answer:

yarga [219]2 years ago

7 0

Here is your answer and an explanation

Answer: y = -2/3x

Explanation:

This can be determined by calculating the gradient of the straight line, using:

m=ΔyΔx

=−6−34−(−2)

=−96

=−32

Then we use the slope-point form of the straight line:

y−y1=m(x−x1)

to give:

y−3=−32(x−(−2))

∴y−3=−32(x+2)

∴y−3=−32x−3

∴y=−32x

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liubo4ka [24]

Answer:

<em>H </em>(20) =<em> E</em>

380

Step-by-step explanation:

So, Rana is trying to <em>multiply her hours with her earnings to get the product</em>, that's where the variable<em> E</em> is. <em>H</em> stands for hours, and so you will <em>multiply it by 20 </em>because that's how much she gets per hour.

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2 years ago

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PLEASE HELP 100 POINTS<br> write an equation of the horizontal line that passes through (-7,-10)

Vedmedyk [2.9K]

Answer:

y + 10 = 0

Step-by-step explanation:

Slope of horizontal line is zero (0)

m = 0

By point slope form of a line.

$y-y_1 =m(x - x_1) \\ \\ y - ( - 10) = 0 \{x - ( - 7) \} \\ \\ y + 10 = 0 \{x + 7\} \\ \\y + 10 = 0 \\ \\$

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2 years ago

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What is the surface area of the rectangular prism? 155 in²

Tpy6a [65]

<span>A. 504 in2 B. 396 in2 C. 312 ... ... A. 155 in2 B. 270 in2 C. 300 in2 D. 310 in2 H=15 l=5 w=4 ... The formula for the rectangular prism surface area is 2(wl+hl+hw).</span><span>300 in2</span>

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2 years ago

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Read the quote, and then answer the question.

Tpy6a [65]

Answer:

x = 5/16

Step-by-step explanation:

2 3 x −1 9 x + 5 = 20 x

x = 5/16

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2 years ago

Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.

fenix001 [56]

Answer:

The angle between vector $\vec{u} = 5\, \vec{i} - 8\, \vec{j}$ and $\vec{v} = 5\, \vec{i} + \, \vec{j}$ is approximately $1.21$ radians, which is equivalent to approximately $69.3^\circ$ .

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

their dot products, and
the product of their lengths.

To be precise, if $\theta$ denotes the angle between $\vec{u}$ and $\vec{v}$ (assume that $0^\circ \le \theta < 180^\circ$ or equivalently $0 \le \theta < \pi$ ,) then:

$\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ .

<h3>Dot product of the two vectors</h3>

The first component of $\vec{u}$ is $5$ and the first component of $\vec{v}$ is also

The second component of $\vec{u}$ is $(-8)$ while the second component of $\vec{v}$ is $1$ . The product of these two second components is $(-8) \times 1= (-8)$ .

The dot product of $\vec{u}$ and $\vec{v}$ will thus be:

$\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}$ .

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both $\vec{u}$ and $\vec{v}$ :

$\| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}$ .
$\| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}$ .

<h3>Angle between the two vectors</h3>

Let $\theta$ represent the angle between $\vec{u}$ and $\vec{v}$ . Apply the formula $\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}$ to find the cosine of this angle:

$\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}$ .

Since $\theta$ is the angle between two vectors, its value should be between $0\; \rm radians$ and $\pi \; \rm radians$ ( $0^\circ$ and $180^\circ$ .) That is: $0 \le \theta < \pi$ and $0^\circ \le \theta < 180^\circ$ . Apply the arccosine function (the inverse of the cosine function) to find the value of $\theta$ :

$\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ$ .

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2 years ago