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masya89 [10]
3 years ago
14

How do I evaluate 564÷24 with a fraction or decimal

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0
564/24 equals to 47/2 or 23.5
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Plz help..............
IrinaVladis [17]
The correct answer is -15 because the absolute value is 15 but there is a negative outside the absolute value lines making it negative :)
7 0
3 years ago
Read 2 more answers
M∠a=(48−x)°m∠b=(9x−38)°m∠c=90°
Fudgin [204]

Answer:

Option C:

  • m∠a = 38°
  • m∠b = 52°
  • m∠c = 90°

Step-by-step explanation:

Hello!

The sum of all angles in a triangle is 180°.

Add up all the angles and solve for x by setting the equation to 180°.

<h3>Solve for x</h3>
  • ∠a + ∠b + ∠c = 180°
  • (48 - x)° + (9x - 38)° + 90° = 180°
  • 10° + 8x + 90° = 180°
  • 8x = 180° - 90° - 10°
  • 8x = 80°
  • x = 10°

Now that we solved for x, we can plug it back into each equation to solve for each angle.

<h3>Angle A</h3>
  • 48° - x
  • 48° - 10°
  • 38°
<h3>Angle B</h3>
  • 9x - 38°
  • 9(10°) - 38°
  • 90° - 38°
  • 52°
<h3>Angle C</h3>
  • 90°

The answer is Option C:

  • m∠a = 38°
  • m∠b = 52°
  • m∠c = 90°
4 0
1 year ago
What is the answer to this question
liraira [26]

Answer:

the answer is z=63

Step-by-step explanation:

6 0
2 years ago
What is the mean, median and mode for...45,50,55,55,55,60,60,60,65,65,70?
Alexxx [7]

Answer:

Mean = 58.18

Median = 60

Modes = 55 and 60

Step-by-step explanation:

To find the mean/average, add up all the numbers and divide the sum by the # of numbers there are (ex. there are 11 numbers so divide the sum by 11).

The median is the middle number of a set.  In this case, the middle number is easy to see because the # of numbers is odd, but if it was even, just find the average of the two middle numbers.

The mode is/are the most frequent number(s) in the set.  In this set, the numbers that appear the most are 55 and 60.

8 0
3 years ago
What time is 5 3/4 hours after 11:32 pm?
elixir [45]

11:32 pm + 5 hours= 4:32pm

4:32 pm + 45 minutes = 5:17 pm

3/4 hour = 45 min


6 0
3 years ago
Read 2 more answers
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