All categories

3 years ago

Pls help i need help pls

Mathematics

2 answers:

Dovator [93]3 years ago

6 0

Answer:

1. x = 32°

2. x = 28°

3. x = 15°

4. x = 30°

5. x = 40°

6. x = 20°

Step-by-step explanation:

All the angles should add up to 90° as they are complementary.

Gnesinka [82]3 years ago

5 0

1.x = 32°
2. x = 28°
3. X = 15°
4. X = 30°
5. x = 40°
6. x = 200

You might be interested in

Write a unit rate for the situation: 2520 kilobytes in 18 seconds

elixir [45]

140 kilobytes per second

7 0

3 years ago

Read 2 more answers

Kevin is a quarterback on the football team.he completed 36 passes during the season.his second-string replacement,Mark complete

anastassius [24]

36 × $\frac{2}{9}$

Since 9 is a factor of 36 you can reduce the 36 to 4 and the 9 to one

Then just multiply what is left

4 <span>× 2 = 8

So, Mark completed 8 passes.</span>

3 0

3 years ago

Here you go this is the full question please help

hammer [34]

I don’t see anything is there supposed to be a picture or?

8 0

2 years ago

Read 2 more answers

How could you change the expression<br> (-8)(-5)(-3) so that the product is<br> positive?

LenKa [72]

Answer:

You make one number positive.

Step-by-step explanation:

A negative number multiplied by a negative number is positive, so that means that if you choose two of the numbers in this expression you will get a positive number. However, there is still one negative number left and you will get a negative product if you multiply, because a positive number multiplied by a negative number is a negative number. If you make this last number positive you will get a positive product.

Hope this helps!

5 0

3 years ago

16 is 10% of what number

marusya05 [52]

let's say is 16% of "x", meaning "x" is the 100%.

we know "x" is 100% and 16% of it is 10, so

$\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 16&10 \end{array}\implies \cfrac{x}{16}=\cfrac{100}{10}\implies \cfrac{x}{16}=10\implies x = 160$

6 0

3 years ago

Read 2 more answers

Pls help i need help pls​

Pls help i need help pls