Answer:
Yes!
Step-by-step explanation:
Let x be the tens place and y be the units place. x and y need to be odd because in other case a or b will not be odd. For example, if x=1 and y=2 a will be 21 but b will be 12 that is not odd.
Now, a+b = xy+yx. Note that xy is not x*y, is just the digits concatenated.Then, there are two cases:
If x+y<10 then xy+yx = (x+y)(x+y) (again, that is not a multiplication is x+y concatenated with x+y) and that is 11*(x+y) a multiple of 11.
If x+y≥10 then xy+yx = (x+y+1)(x+y-10) because x+y<20.
Now we are going to see that last result without the concatenation, as a sum, that is
(x+y+1)*10 + x+y-10 = 10x+10y+10+x+y-10 = 11x+11y = 11(x+y). This result is clearly a multiple of 11.
In conclusion, in all cases the result of a+b is a multiple of 11.
