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Nikolay [14]
3 years ago
6

What did I do wrong. I thought it was 15

Mathematics
2 answers:
Tatiana [17]3 years ago
8 0
The answer is A. 10 A zebra runs at a pace of 40 MPH while a gazelle runs at a speed of 50 MPH. There is a 10 MPH difference. MPH= miles per hour
CaHeK987 [17]3 years ago
3 0
Its not 15 isnt it 10
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G(x)= 3x − 3; Find g(−6)
Irina18 [472]
<span>g(x)= 3x − 3
</span><span>g(−6)

g(-6) = 3(-6) - 3
g(-6) = -18 - 3
g(-6) = -21

The answer is -21.</span>
4 0
3 years ago
Read 2 more answers
Solve the following quadratic for the values x
mamaluj [8]

Answer:

x² + 6x - 27 = 0

x² + 9x - 3x - 27 = 0

x ( x + 9 ) - 3 ( x + 9 ) = 0

( x + 9 ) ( x - 3 ) = 0

Thus ,

x = -9 or x = 3

I hope it helps you

#Indian : )

8 0
3 years ago
Read 2 more answers
Rolf spent 15 hours last week practicing his saxophone if 3/10 of the time was spent practicing warm up routines, how much time
NeTakaya
3/10 of the time = time spent on practicing warm up routines...
Time spent = 15 hours
remember that 'of' is usually multiply (x)
so ---- 3/10 x 15 =4.5 hrs

Hope this helps
3 0
3 years ago
walker is reading a book that is 792 pages. He reads 15 pages a day during the week, and 25 pages a day during the weekend. Afte
Gnesinka [82]

Answer: The total number of pages does Walker still have left to read before he finishes the book is 167 and this can be determined by using the arithmetic operations.

Step-by-step explanation: edge 2021!

5 0
2 years ago
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For the following pair of functions, find (f+g)(x) and (f-g)(x).
ch4aika [34]

Given:

The functions are

f(x)=4x^2+7x-5

g(x)=-9x^2+4x-13

To find:

The functions (f+g)(x) and (f-g)(x).

Solution:

We know that,

(f+g)(x)=f(x)+g(x)

(f+g)(x)=4x^2+7x-5-9x^2+4x-13

(f+g)(x)=(4x^2-9x^2)+(7x+4x)+(-5-13)

(f+g)(x)=-5x^2+11x-18

And,

(f-g)(x)=f(x)-g(x)

(f-g)(x)=(4x^2+7x-5)-(-9x^2+4x-13)

(f+g)(x)=4x^2+7x-5+9x^2-4x+13

(f+g)(x)=(4x^2+9x^2)+(7x-4x)+(-5+13)

(f-g)(x)=13x^2+3x+8

Therefore, the required functions are (f+g)(x)=-5x^2+11x-18

and (f-g)(x)=13x^2+3x+8.

7 0
3 years ago
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