Question

(2x-y)(3x+y)

Answer 1

For this case we must solve the following product:

$(2x-y) (3x + y) =$

We apply distributive property considering that:

$+ * + = +\\+ * - = -$

So:

$(2x) (3x) + (2x) (y) - (y) (3x) - (y) (y) =$

To multiply powers of the same base, the same base is placed and the exponents are added:

$6x^{1 + 1} + 2xy-3xy-y^{1 + 1} =$

Different signs are subtracted and the sign of the major is placed:

$6x ^ 2-xy-y ^ 2$

So, the solution is: $6x ^ 2-xy-y ^ 2$

Answer:

Option A