Well, let's see . . .
You said that (a) men can dig (c) holes in (b) hours.
So . . . It takes (a) men (b / c) hours to dig one hole.
And . . . It takes One man (a b / c) hours to dig one hole.
Now . . . There are (b) holes to be dug.
It would take one man (a b / c)·(b) = (a b² / c) hours to dig them all.
But if you had 'x' men, it would only take them (c) hours to do it.
So c = (a b² / c) / x
x c = (a b² / c)
x = a b² / c² men .
Now, I lost the big overview while I was doing that,
and just started following my nose through the fog.
So I have to admit that I'm not that confident in the answer.
But gosh durn it. That's the answer I got, and I'm stickin to it.
Rrarrup !
Answer:
C
Step-by-step explanation:
This is the shows the constant value on the X-axis
Answer:
The value of this expression is -35.
Step-by-step explanation:
Let's use the order of operations (PEMDAS), to solve this problem.
In conclusion, the value of this expression is -35. Hope this helped :D
The answer is: 10 x¹³ y¹⁰ .
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1x^8 * 2y^(10) * 5x^5 =
1* 2* 5 * x^8 * x^5 * y^(10) =
10 * x^(8+5) * y^(10) =
10 * x^(13) * y^(10) = 10 x^(13) y^10 ; write as:
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10 x¹³ y¹<span>⁰ .
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