Answer:
Quadrilateral ABCD is not a square. The product of slopes of its diagonals is not -1.
Step-by-step explanation:
Point A is (-4,6)
Point B is (-12,-12)
Point C is (6,-18)
Point D is (13,-1)
Given that the diagonals of a square are perpendicular to each other;
We know that the product of slopes of two perpendicular lines is -1.
So, slope(m) of AC × slope(m) of BD should be equal to -1.
Slope of AC = (Change in y-axis) ÷ (Change in x-axis) = (-18 - 6) ÷ (6 - -4) = -24/10 = -2.4
Slope of BD = (Change in y-axis) ÷ (Change in x-axis) = (-1 - -12) ÷ (13 - -12) = 11/25 = 0.44
The product of slope of AC and slope of BD = -2.4 × 0.44 = -1.056
Since the product of slope of AC and slope of BD is not -1 hence AC is not perpendicular to BD thus quadrilateral ABCD is not a square.
Answer:
Step 1: Identify the Problem. ...
Step 2: Analyze the Problem. ...
Step 3: Describe the Problem. ...
Step 4: Look for Root Causes. ...
Step 5: Develop Alternate Solutions. ...
Step 6: Implement the Solution. ...
Step 7: Measure the Results.
Answer: The three different equations will be
Step-by-step explanation:
We have to write three equation that have x = 5 as a solution:
1) First equation will be
2) Second equation will be
3) Third equation will be
Hence, the three different equations will be
Answer:
see explanation
Step-by-step explanation:
The opposite angles of an inscribed quadrilateral are supplementary, thus
5x + 20 + 7x - 8 = 180
12x + 12 = 180 ( subtract 12 from both sides )
12x = 168 ( divide both sides by 12 )
x = 14
Thus
∠ RQP = 10x = 10(14) = 140°
∠PSR = 180° - 140° = 40° ( opposite angles are supplementary )
∠ SRQ = 7X - 8 = 7(14) - 8 = 98 - 8 = 90°
∠ QPS = 5x + 20 = 5(14) + 20 = 70 + 20 = 90°
