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miv72 [106K]
3 years ago
6

What’s 4 divided by 3.3

Mathematics
2 answers:
Olin [163]3 years ago
8 0

Answer: 1.21 repeated

Step-by-step explanation:

lilavasa [31]3 years ago
7 0

Answer:

it is 1.21repeated hope this helps

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I believe the answer is 40

24/3 is 8 therefore if we did 5 • 8 we should get the correct answer which is 40
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X/6-5=-13 .............................. . . . .
sattari [20]

Answer:

-48

Step-by-step explanation:

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3 years ago
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Find the measure of angle AEC
andreev551 [17]
Aec= 40

Explanation because it’s a 90 degree angle and dea = 50
So 90-50=40
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4 years ago
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The two box plots summarize the number of hours spent in the weight room for all the players on the football team
iragen [17]

Options:

A. Players at school 1 typically spent more time in the weight room than players at school 2.

B. The middle half of the data for school 1 has more variability than the middle half of the data for school 2.

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

D. The total number of hours spent in the weight room for players at school 2 is greater than the total number of hours for players at school 1.

(See attachment for the box plots)

Answer:

C. The median hours spent in the weight room for school 1 is less than the median for school 2 and the interquartile ranges for both schools are equal.

Step-by-step explanation:

The median for school 1 is the value at the vertical line that divides the box of the box plot display of for school 1, which is 8

School 2 has a median of 9.

As we can see, the median for school 1 is less than the median of school 2.

Interquartile range is the range of the box.

Interquartile range for school 1 = 10 - 4 = 6

Interquartile range for school 2 = 13 - 6 = 6

As we can also see, the interquartile range for school 1 and that of school 2 are equal.

7 0
4 years ago
In ΔJKL, k = 3.7 cm, ∠K=15° and ∠L=41°. Find the length of j, to the nearest 10th of a centimeter.
Alexandra [31]

Answer:

The length of side j is 11.85cm

Step-by-step explanation:

Given that

In triangle JKL,

\angle k=15

\angle l=41

Side k=LJ=3.7cm

To find side j=KL:

By using sine rule,

We can write as

\frac{SinK}{LJ} = \frac{SinL}{JK} = \frac{SinJ}{KL} \\\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{SinJ}{KL}

Using property of triangle,

\angle k+\angle l+\angle j=180

15+41+\angle j=180

\angle j=124

\frac{Sin15}{3.7} = \frac{Sin41}{JK} = \frac{Sin124}{KL}\\\frac{Sin15}{3.7} = \frac{Sin124}{KL}\\KL=3.7\frac{Sin124}{Sin15}\\KL=3.7\frac{0.8290}{0.2588}\\KL=11.85cm

Thus,

The length of side j is 11.85cm

8 0
3 years ago
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