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umka21 [38]
3 years ago
5

A golfer’s arm rotates 1/2 of a revolution in 1/10 of a second. If the angular displacement is measured in radians, which statem

ents are true? Check all that apply. The angular velocity is 10π rad/sec. multiple can be chosen
A)The angular velocity is 10π rad/min.
B)The angular velocity is 60π rad/min.
C)The angular velocity is 600π rad/sec.
D)The angular velocity is 600π rad/min.
Mathematics
2 answers:
RSB [31]3 years ago
7 0

Answer:

A and D

Step-by-step explanation:

<h2>a)</h2>

\frac{.5 rev}{.1 } = 5 rev/sec

-- Convert to radians

\frac{5 rev}{1 sec} * 2\pi =10 \frac{radians}{sec}

<h2 /><h2>d) </h2>

10\frac{rad}{sec}*\frac{60 sec}{1 min}  = 600 rad/min

anyanavicka [17]3 years ago
6 0
We know that

<span>The angular velocity is 10π rad/sec
step 1
convert to rad/min
1 min-----60 sec
X min----> 1 sec
X=1/60 min
V=</span>10π rad/(1/60)------> V=600 π rad/min

the answer is the option 
<span>D)The angular velocity is 600π rad/min.</span>
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There were 28,000 wolves in North Carolina in the 1950, but the population has declined by 8% each year.
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Answer questions 13. And 14. Please! Show minimal work...
ale4655 [162]

13. The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14. The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Step-by-step explanation:

Let us revise the transformation of the trigonometric function:

y = a f[b(x + c)] + d, where

  • Amplitude is a
  • f represents the trigonometry function
  • Period is 2π/b
  • Phase shift is c (positive is to the left)
  • Vertical shift is d

13.

∵ y = a sin( \frac{2\pi t}{T} ), where a is the amplitude

   and T is the wave in seconds

∵ The amplitude is 4

∴ a = 4

∵ The period is 4π

∴ T = 4π

From the rules above

∵ The period is 2π/b

∴ T = \frac{2\pi }{B}

∴ 4π = \frac{2\pi }{b}

- By using cross multiplication

∴ 4π(b) = 2π

- Divide both sides by 4π

∴ b = \frac{1}{2}

∵ The phase shift is -\frac{4}{3}\pi

∵ c is the phase shift

∴ c = -\frac{4}{3}\pi

∵ The vertical shift is -2

∵ d is the vertical shift

∴ d = -2

Now substitutes the values of a, b, c and d in the form of the equation below

∵ y = a sin[b(t + c)] + d

∴ y=4sin[\frac{1}{2}(t-\frac{4}{3})]-2

You can write it as y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

The equation of the given function is y=4sin[\frac{(t-\frac{4}{3})}{2}]-2

14.

y = cot[b(t + c)] + d

∵ The period = π

∵ The period is 2π/b

- Equate π by 2π/b to find b

∴ π = \frac{2\pi }{b}

- By using cross multiplication

∴ π(b) = 2π

- Divide both sides by π

∴ b = 2

∵ The phase shift is -\frac{1}{3}\pi

∵ c is the phase shift

∴ c = -\frac{1}{3}\pi

∵ The vertical shift is 2

∵ d is the vertical shift

∴ d = 2

Now substitutes the values of b, c and d in the form of the equation below

∵ y = cot[b(t + c)] + d

∴ y=cot[2(t-\frac{1}{3})]+2

The equation of the cotangent function is y=cot[2(t-\frac{1}{3})]+2

Learn more:

You can learn more about trigonometry function in brainly.com/question/3568205

#LearnwithBrainly

5 0
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