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Nutka1998 [239]
3 years ago
11

Which expression is equivalent to √-60? A) -2√15 B) -4√15 C) 4i√15 D) 2i√15

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
8 0

Answer:

d) 2i√15

Step-by-step explanation:

60/4 is 15 so you can take out the square of 2 and the -

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This isn't something specific I need to know for school, I'm just curious. I know the most commonly used variables are x, y, and
andre [41]

Answer:

Any letter you want

Step-by-step explanation:

The letters used for variables don't matter. What matters is what the variables represent: their numerical value. Variables are just to help identify what needs solving. Other common variables are a, b, and c which are found frequently in trigonometry. To answer your question, there are no "next letters." You can use any letter you'd like as a variable because it holds the same numerical value. Basically, the whole alphabet is at your disposal.

4 0
3 years ago
From Statistics and Data Analysis from Elementary to Intermediate by Tamhane and Dunlop, pg 265. A thermostat used in an electri
Leviafan [203]

Answer:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

Step-by-step explanation:

Information given

data: 202.2 203.4 200.5 202.5 206.3 198.0 203.7 200.8 201.3 199.0

We can calculate the sample mean and deviation with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

\sigma=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=201.77 represent the sample mean    

s=2.41 represent the sample standard deviation    

n=10 sample size    

\mu_o =200 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic

p_v represent the p value for the test

Hypothesis to test

We want to determine if the true mean is equal to 200, the system of hypothesis are :    

Null hypothesis:\mu = 200    

Alternative hypothesis:\mu = 200    

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)    

The statistic is given by:

t=\frac{201.77-200}{\frac{2.41}{\sqrt{10}}}=2.32    

The degrees of freedom are given by:

df=n-1=10-1=9  

The p value for this case is given by:

p_v =2*P(t_{(9)}>2.32)=0.0455    

For this case since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly different from 200 F.

4 0
3 years ago
Help Me With These <br> #Geometry
Damm [24]
They are mad as easy try it on your own your answer is suppose to be 80
5 0
4 years ago
⚠️PLEASE HELP⚠️
alexdok [17]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
What is ......<br><br>(23×10)+(23×7)=​
babunello [35]

Answer:

391

Step-by-step explanation:

(23 x 10) + (23 x 7) =

230 + 161 =

391

Hope this helps! Please mark as brainliest.

5 0
4 years ago
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