This problem can be modeled by the picture shown below. We notice that we are given to side lengths, specifically legs, of the triangle. Therefore, we can use the Pythagorean Theorem, which states that a^2+b^2=c^2, where a and b are legs and c is the hypotenuse. So we can do:
16^2+12^2=c^2
256+144=c^2
400=c^2
The square root of 400 is
20, which is our hypotenuse.
(You might wonder why we used 12, that is because the whole base length is 24, but we only need half of the base to use the Pythagorean Theorem. 24/2 is 12).
:)
I hope this helps you
5x <74-29
5x <45
x <9
Answer:
ok
Step-by-step explanation:
6% of 38= 2.28
115% of 212=243.8
32% of 24= 7.68
The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>