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True [87]
3 years ago
14

What type of triangle is angle is 118 and is 42 inches

Mathematics
1 answer:
Lina20 [59]3 years ago
3 0
If the triangle has an obtuse angle (>90 degrees), it can be classified as an obtuse triangle Not sure where the 42 inches is used Hope this helps
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-x/3 = 2 x = -6 x = 6 x = -1
ikadub [295]

The question is -x/3 = 2 which is 1/3x=2

multiply both sides by 3, and you'll get x = 6

8 0
3 years ago
Four more than the quotientof 25 divided by 5
mel-nik [20]

Step-by-step explanation:

25/5 + 4 = 5 + 4 = 9

is that what you needed ?

4 0
2 years ago
Read 2 more answers
This is 10 points plz help ( NO LINKS )
SSSSS [86.1K]

Answer:

H. 8%

Step-by-step explanation:

27 + 19 + 4 = 50 (total weight)

4% of 50 = 2

5% of 50 = 2.5

8% of 50 = 4

12% of 50 = 6

Therefore the answer would be H, 8% because 8% of 50 is 4

3 0
3 years ago
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Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. y = 7x6, y
IgorC [24]

Answer:

The volume is \frac{490\pi}{39} cubic units.

Step-by-step explanation:

The given curve is

y=7x^6

The given line is

y=7x

Equate both the functions to find the intersection point of both line and curve.

7x^6=7x

7x^6-7x=0

7x^6-7x=0

7x(x^5-1)=0

7x=0\rightarrow x=0

x^5-1=0\rightarrow x=1

According to washer method:

V=\pi \int_{a}^{b}[f(x)^2-g(x)^2]dx

Using washer method, where a=0 and b=1, we get

V=\pi \int_{0}^{1}[(7x)^2-(7x^6)^2]dx

V=\pi \int_{0}^{1}[49x^2-49x^{12}]dx

V=49\pi \int_{0}^{1}[x^2-x^{12}]dx

V=49\pi [\frac{x^3}{3}-\frac{x^{13}}{13}]_0^1

V=49\pi [\frac{1^3}{3}-\frac{1^{13}}{13}-(0-0)]

V=49\pi [\frac{1}{3}-\frac{1}{13}]

V=49\pi (\frac{13-3}{39})

V=49\pi (\frac{10}{39})

V=\frac{490\pi}{39}

Therefore the volume is \frac{490\pi}{39} cubic units.

5 0
3 years ago
Write the point slope equation of the line through (7,-2) with slope of 1/2.
ahrayia [7]

Answer:

y = 0.5x - 5.5

Step-by-step explanation:

slope = 0.5, so this is the x coefficient.

y intercept = -2 - (7 x 0.5) = -5.5

4 0
3 years ago
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