Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
For this case the new area is the sum of two areas:
Area = rectangular gym + weight room
Area = (4x² + 520) ft²
In addition, we know that
rectangular gym = 4x ^ 2 ft²
Therefore, the term 520 represents a new weight room
answer
The constant term represent a new weight room
You would eat 3/10 of the box because 3/4 times 2/5 is 3/10. Whenever you see the word "of" it means multiplication.
88!!! thank you i belive that is it
Answer:
16
Step-by-step explanation:
4x3=12 tins of white paint
12+4=16 total tins
