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givi [52]
3 years ago
5

Probability against a spinner landing on a green space if the spinner had 8 sections & 3 of them are green

Mathematics
2 answers:
Tom [10]3 years ago
6 0
Probability AGAINST a spinner landing on green ...
if 3 are green, then 5 are not green...
5/8 = 0.625 rounds to 0.63 = 63% <===
Pani-rosa [81]3 years ago
3 0

Answer:

The answer is 63%.

Step-by-step explanation:

Total number of sections in the spinner = 8

Total number of green sections in the spinner = 3

Hence, the Probability against a spinner landing on a green space if the spinner had 8 sections & 3 of them are green is = 1-\frac{3}{8}=\frac{5}{8}

= 0.625 ≈ 62.5% rounding to 63%.

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\begin{gathered} For\text{ the point }(-9,-2) \\ x=-9,y=-2 \\ 4x-6y\leq-18 \\ 4(-9)-6(-2)=-36+12=-24 \\ Since\text{ }-24

\begin{gathered} For\text{ the point }(0,3) \\ x=0,y=3 \\ 4x-6y\leq-18 \\ 4(0)-6(3)=0-18=-18 \\ Since\text{ }-18=-18,\text{ then }(0,3)\text{ is a solution} \end{gathered}

\begin{gathered} For\text{ the point }(5,-3) \\ x=5,y=-3 \\ 4x-6y\leq-18 \\ 4(5)-6(-3)=20+18=38 \\ Since\text{ }38>-18,\text{ then }(5,-3)\text{ is not a solution} \end{gathered}

\begin{gathered} For\text{ the point }(8,5) \\ x=8,y=5 \\ 4x-6y\leq-18 \\ 4(8)-6(5)=32-30=2 \\ Since\text{ }2>-18,\text{ then }(8,5)\text{ is not a solution} \end{gathered}

Therefore, the correct answers are selected as shown below;

7 0
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