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3 years ago

Please help this is the last problem on my homework and I don’t understand how to do it

Mathematics

2 answers:

malfutka [58]3 years ago

6 0

When the lines are parallel and angles are given, and since a straight line is 180°, the 2 angles of the line intersecting the parallel lines have to add up to be 180. Therefore,
21. 31°
22. 96°
23. 149°
24. 84°
25. 53°

4vir4ik [10]3 years ago

4 0

Answer:

21. m<2 = 31 degree

22. m<11 = 96 degrees

23. m<5 = 127 degree

24. m<12 = 84 degree

25. m<6 = 53 degree

Step-by-step explanation:

21 explain) m<8 = m<1 = 149 degree b/c Alternate angle rule

m<1 + m<2 = 180 b/c straight line is 180 degrees

m<2 = 180 - m<1

m<2 = 180 - 149 = 31 degrees

25 explain) m<3 = m<6 = 53 degree b/c Alternate angle rule

22. explain) m<7 = m<8 - 180 b/c straight line is 180 degrees

m<7 = 180-149 = 31

m<11 = 180 - m<7 - m<6

m<11 = 180 -31 -53 = 96 degrees

24. explain) 180 = m<11 + m<12 b/c straight line is 180 degrees

180 - m<11 = m<12

180 - 96 = m<12

84 = m<12

25. explain) m<3 = m<6 = 53 degree b/c Alternate angle rule

180 = m<5 + m<6 b/c straight line is 180 degrees

180 - m<6 = m<5

180 - 53 = m<5

127 = m<5

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The ages of the employees at Solar Systems, Inc. is normally distributed with a mean of 32.7 years and a standard deviation of 1

svetoff [14.1K]

Answer:

6.7% of employees at Solar Systems, Inc. are younger than 30 years old

Step-by-step explanation:

The mean of ages of the employees at Solar Systems is 32.7 years

Mean = $\mu = 32.7$

Standard deviation = $\sigma = 1.8 years$

We are supposed to find What percentage of employees at Solar Systems, Inc. are younger than 30 years old i.e.P(x<30)

So, $Z=\frac{x-\mu}{\sigma}$

$Z=\frac{30-32.7}{1.8}$

Z=-1.5

Refer the z table for p value

So,p value = 0.0668

So P(x<30)=0.0668= 6.68% = 6.7%

So, 6.7% of employees at Solar Systems, Inc. are younger than 30 years old

7 0

3 years ago

Solve this equation: 4+k=11

Law Incorporation [45]

Answer:

k=7

Step-by-step explanation:

4+k=11

subtract 4 from both sides to isolate k

k= 7

3 0

3 years ago

A certain club has 20 members. What is the ratio of the number of 5-member committees that can be formed from the members of the

MissTica

Answer:

Step-by-step explanation:

This is a combination question.

In the first instance, we select 5 from 20 and in the second case , we select 4 from 20.

The total number of ways to solve the first instance is 20C5 = 15504 ways

The total number of ways to solve the second instance is 20C4 = 4,845

The ratio of the first to the second scenario is 15,504/4,845 = 3.2 = 16 to 5

8 0

3 years ago

Making handcrafted pottery usually takes two major steps:wheel throwing and firing. The time of wheel throwing and thetime of fi

levacccp [35]

Answer:

a) $P(R$

And we can find this probability using the normal standard table or excel and we got:

$P(z$

b) $P(R>110)=P(\frac{R-\mu}{\sigma}>\frac{110-\mu}{\sigma})=P(Z>\frac{110-100}{3.606})=P(Z>2.774)$

And we can find this probability using the complement rule and the normal standard table or excel and we got:

$P(z>2.774)=1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the time for the step 1 and Y the time for the step 2, we define the random variable R= X+Y for the total time and the distribution for R assuming independence between X and Y is:

$R \sim N(40+60 = 100,\sqrt{2^2 +3^2}= 3.606 s)$

Where $\mu=65.5$ and $\sigma=2.6$

We are interested on this probability

$P(R$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{R-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(R$

And we can find this probability using the normal standard table or excel and we got:

$P(z$

Part b

$P(R>110)=P(\frac{R-\mu}{\sigma}>\frac{110-\mu}{\sigma})=P(Z>\frac{110-100}{3.606})=P(Z>2.774)$

And we can find this probability using the complement rule and the normal standard table or excel and we got:

$P(z>2.774)=1-P(Z$

8 0

3 years ago

Read 2 more answers

Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 76.676.6

faltersainse [42]

Answer:

Step-by-step explanation:

Researchers measured the data speeds for a particular smartphone carrier at 50 airports.

The highest speed measured was 76.6 Mbps.

n= 50

X[bar]= 17.95

S= 23.39

a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?

If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps

b. How many standard deviations is that [the difference found in part (a)]?

To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation

Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations

c. Convert the carrier's highest data speed to a z score.

The value is X= 76.6

Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51

d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?

The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.

I hope it helps!

3 0

3 years ago