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Tcecarenko [31]
3 years ago
5

Which of the following equations corresponds to the graph below?

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
6 0

Answer: D: Y= -2x - 1

Step-by-step explanation:

y= mx+b

m= slope

b= y intercept

notka56 [123]3 years ago
6 0

Answer:

D

Step-by-step explanation:

Find slope.

rise over run

It goes up two and back one, so the slope is -2.

y int is at -1. plug it into y = mx + b

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48 ft^2

Step-by-step explanation:

5.5 times 6 equals 33 (larger square part)

2.5 times 6 equals 15 (two triangles combined so you dont have to 1/2)

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3 years ago
ILL GIVE U BRAINLIEST PLZZ HELP I DO FLVS
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c the answer is c


Step-by-step explanation:


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3 years ago
Expansion Numerically Impractical. Show that the computation of an nth-order determinant by expansion involves multiplications,
posledela

Answer:

  • number of multiplies is n!
  • n=10, 3.6 ms
  • n=15, 21.8 min
  • n=20, 77.09 yr
  • n=25, 4.9×10^8 yr

Step-by-step explanation:

Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...

  mpy[n] = n·mp[n-1]

  mpy[2] = 2

So, ...

  mpy[n] = n! . . . n ≥ 2

__

If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...

  10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10

Then the larger matrices take ...

  n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min

  n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years

  n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years

_____

For the shorter time periods (less than 100 years), we use 365.25 days per year.

For the longer time periods (more than 400 years), we use 365.2425 days per year.

8 0
3 years ago
A rope 13 meters long will just reach from the top of a flagpole to a point on the ground 12 meters from teh base of the flagpol
goldfiish [28.3K]

Answer:

the height of the flagpole is 5 meters

Step-by-step explanation:

The computation of the height of the flagpole is given below

Given that

the length of the rope is 13 meters

And, the ground would be 12 meters

Based on the above information, the height of the flagpole is

= √13^2 - √12^2

= √169 - √144

= √25

= 5 meters

hence the height of the flagpole is 5 meters

5 0
3 years ago
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