RADIOS is a hexagon that has six equal sides. The coordinates of side AD are (–4, 2) and (7, 2). What is the perimeter of the he
2 answers:
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Answer:
Part a) The coordinates of the suspect's car at its final destination are (4,4)
Part b) The distance traveled by the suspect was 10 miles
Part c)
Step-by-step explanation:
The correct question in the attached figure
Part a) What are the coordinates of the suspect's car at its final destination?
we know that
The original position is the origin of a Cartesian coordinate system (0,0)
1) The suspect's car was tracked going 5 mi due east
That means----> 5 mi at right
the new coordinates are (5,0)
2) The suspect's car was tracked going 4 mi due north
That means----> 4 mi up
the new coordinates are (5,4)
3) The suspect's car was tracked going 1 mi due west
That means----> 1 mi at left
the new coordinates are (4,4)
therefore
The coordinates of the suspect's car at its final destination are (4,4)
Part b) What was the distance traveled by the suspect?
The distance traveled is
5 mi due east + 4 mi due north + 1 mi due west
therefore
The distance traveled by the suspect was 10 miles
Part c) What is the distance as the crow flies between the original position and the final position of the suspect's car?
the formula to calculate the distance between two points is equal to
Remember that
The original position was (0,0) and the final position was (4,4)
substitute in the formula
9514 1404 393
Answer:
see below
Step-by-step explanation:
Setting x=0, you can find the y-intercept:
y = 4
Setting y = 0, you can find the x-intercept:
2x = 4
x = 2
The boundary line can be drawn through these intercept points, (0,4) and (2,0). Because the "equal to" case is not included, the boundary line will be dashed.
The y variable is on the open side of the comparison symbol (y>), so the shading is above the boundary line. That is where y-values are greater than those on the line.
Answer:
- see the attachment
- (x, y) = (1, 1)
Step-by-step explanation:
1. Since you have y > ..., the boundary line is dashed and the shading is above it (for y-values greater than the values on the line). The boundary line is ...
y = 2x+3
which has a y-intercept of 3 and a slope (rise/run) of 2. A graph is attached.
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2. You can add the two equations to eliminate y:
(3x +y) +(x -y) = (4) +(0)
4x = 4
x = 1
1 - y = 0 . . . . substitute into the the second equation
1 = y . . . . . . . add y
The solution is (x, y) = (1, 1).
