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Dahasolnce [82]
3 years ago
6

Pls help pls 10 points!!! Pls

Mathematics
1 answer:
worty [1.4K]3 years ago
7 0

Answer:

-5

Step-by-step explanation:

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hoa [83]

Answer:

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7 0
4 years ago
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The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =
avanturin [10]
Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
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The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

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x = ( 1 + √41 ) / 4  or 1.85
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Therefore, the zeros of the quadratic equation are 1.85 and -1.35. 
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3 years ago
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