25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
It would be an odd number of teams. What I did was add 43 and 34 together. Which gave me 77. So 77 people total wanted to race. There can only be 8 racers on each team. Each means to divide. So I divided 8 and 77. It gave me 9 with a remainder of 5. So there will e 9 teams and 5 racers left out. (:
Answer:
23,936
Step-by-step explanation:
so get your 17600 times it by 0.36 which gets you 6,336 then add that to 17,600 =23,936
That's how you get your answer
Answer:
(7x+3) (x-1)
hope this helps!!:)
Step-by-step explanation:
I think 2/4 but I'm not 100% sure sry
