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Alinara [238K]
3 years ago
10

A plane traveled 460 mph with the wind and 400 mph against the wind. Find the speed of the plane in still air and the speed of t

he wind.
Mathematics
1 answer:
Fudgin [204]3 years ago
7 0
Let's say the speed of the plane is "p", and the speed of the wind is "w".

when the plane goes with the wind, is not really going "p" mph fast, is really going "p + w" mph fast, because the wind is adding speed to it.

likewise when the plane is going against the wind, is also not going "p" fast is going "p - w" mph fast.  Therefore,

\bf \begin{cases}
p+w=460\implies \boxed{w}=460-p \\
p-w=400\\
----------\\
p-\left( \boxed{460 - p} \right)=400
\end{cases}
\\\\\\
2p-460=400\implies 2p=860\implies p=\cfrac{860}{2}\implies p=430
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Since we have x=4.75 for the directrix, this tells us that the parabola's axis of symmetry runs parallel to the x-axis.  This means we will use the standard form

(y-k)²=4p(x-h), where (h, k) is the vertex, (h+p, k) is the focus and x=h-p is the directrix.

Beginning with the directrix:

x=h-p=4.75
h-p=4.75

Since the vertex is at (0, 0), this means h=0 and k=0:

0-p=4.75
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Substituting this into the standard form as well as our values for h and k we have:
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<em>Answer</em>

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