Sub x = 2-y^2 to Q, we get:
Q = 3(2-y^2)*y^2
let y^2 = k
Q = 3(2-k)k = 3(2k-k^2)
2k-k^2 has a max when k = 1
Then y^2 = 1 -> y = 1 or -1
7/12 is closer to 0.583333
Answer:
$18.75
Step-by-step explanation:
Let
y = Total cost
x = number of kilometers
The equation:
y = 3.75 + 1.50x
If x = 10 km
y = 3.75 + 1.50(10)
= 3.75 + 15
= 18.75
y = $18.75
y = Total cost = $18.75
You start by subtracting: 16000-1200= 14800
Then you divide 14800 by how many feet the plane rises per minute
14800/945=16 minutes
The answer is 16 minutes
22 increases by 0.9
24 increases by 4 and 1/2
25 increases by 4.3
Just subtract the number from the number after it to find how to find the next numbers in the sequence
