7h + 6b = 35.50
5h + 6b = 30.50
The difference between the 2 totals spent is $5, and there were the same number of burgers, but 2 fewer hotdogs. So $5/2 = $2.50, the cost of a hot dog. Substitute that into the equations to solve for burgers (b)
5(2.50) + 6b = 30.50
12.50 + 6b = 30.50
6b = 18
b = 3
Check the work:
7(2.50) + 6(3) =
17.50 + 18 = 35.50
Hey there!
To find the equation of a line, we first have to determine its slope knowing that parallel lines have the same slope.
Let the line that we are trying to determine its equation be
and the line that is parallel to
be
.
passes through the points (9 , 2) and (3 , -5) which means that we can find its slope using the slope formula:
⇒Subtitute the values :

.
Assuming that we want to get the equation in Slope-Intercept Form, let's substitute m = 7/6:
Slope-Intercept Form:
We know that the coordinates of the point (0 , -3) verify the equation since it is on the line
. Now, replace y with -3 and x with 0:

Therefore, the equation of the line
is 
▪️Learn more about finding the equation of a line that is parallel to another one here:
↣brainly.com/question/27497166
Answer: there is room for
approximately 33.49 in^3 of coconut milk.
Step-by-step explanation:
Hi, to answer this question first, we have to find the diameter of the inside sphere by subtracting the thickness of the coconut meat (1in)to the diameter of the entire coconut:(5in)
5-1 =4in (diameter)
Since
Diameter= 2radius
4 /2=r
2in=r
Applying the next formula:
Volume of a sphere: 4/3 π r^3
Replacing with the values given:
V = 4/3 (3.14) 2^3 = 33.49 in3
Side1 + side2 + side 3 = 84
side1 is the shortest side, and its length is x.
side2 is the middle side, and its length is x + 7
side3 is the longest side, and its length is 2x - 7
x + x + 7 + 2x - 7 = 84
4x = 84
x = 21
side1 = x = 21
side2 = x + 7 = 21 + 7 = 28
side3 = 2x - 7 = 2(21) - 7 = 42 - 7 = 35
The length of the sides are 21 m, 28 m, and 35 m.
To get 20/10 as a mixed number you would have to take 20 and divide it by 10. Once you do that your answer should be 2.