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Lemur [1.5K]
3 years ago
8

Find the intercepts of 6x – 2y = -24.

Mathematics
1 answer:
viva [34]3 years ago
7 0
The intercepts are where the line crosses the x and y axises

the x intercept is where the line crosses the x axis or where y=0
the y intercept is where the line crosses the y axis or where x=0


so find them by setting other to zero

xint, y=0
6x-0=-24
6x=-24
divide 6
x=-4
xint is x=-4

yint, x=0
0-2y=-24
-2y=-24
divide -2
y=12
yint is y=12





xint: x=-4
yint: y=12

given options A.x=4, y=-12 B.x=-12, y=4 C.x=-4, y=12 D. x=12, y=4

the answer is C


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Joe is 1.6m tall. His shadow is 2m long when he stands 3m from the base of a floodlight.height1.6 m2m3mWhat is the height of the
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We are given the height of Joe which is 1.6 meters, the length of his shadow is 2 meters when he stands 3 meters from the base of the floodlight. 

First, we have to illustrate the problem. Then we can observe two right triangles formed, one is using Joe and the length of the shadow, the other is the floodlight and the sum of the distance from the base plus the length of the shadow. To determine the height of the floodlight, use ratio and proportion:

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The ordered pair (-4, -5) is a solution of the following system of equations 2x+y=13 19x+13y=15
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Answer:

Step-by-step explanation

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3 years ago
Find the discriminant of x2-6x -10 = 0, and determine the number of real solutions of the equation.​
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Answer:

76

2 real solutions

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

Standard Form: ax² + bx + c = 0

Discriminant: b² - 4ac

  • Positive - 2 solutions
  • Equal to 0 - 1 solution
  • Negative - No solutions/Imaginary

Step-by-step explanation:

<u>Step 1: Define</u>

x² - 6x - 10 = 0

<u>Step 2: Identify Variables</u>

<em>Compare quadratic.</em>

x² - 6x - 10 = 0 ↔ ax² + bx + c = 0

a = 1, b = -6, c = -10

<u>Step 3: Find Discriminant</u>

  1. Substitute in variables [Discriminant]:                                                            (-6)² - 4(1)(-10)
  2. [Discriminant] Evaluate exponents:                                                                36 - 4(1)(-10)
  3. [Discriminant] Multiply:                                                                                    36 + 40
  4. [Discriminant] Add:                                                                                          76

This tells us that our quadratic has 2 real solutions.

8 0
2 years ago
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