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2 years ago

GEOMETRY HELP PLEASE URGENT

Mathematics

1 answer:

KiRa [710]2 years ago

5 0

Lets O is the center of the circle and Lets A is a point cut on CD from O

mCD = m<COD

OA is perpendicular bisector of CD so OA = 1/2 CD = 1/2(12.7) = 6.35

Sin (DOA) = AD/OD = 6.35 / 9.06

Sin DOA = 0.7009

<DOA = 44.5°

<COD = 2 x 44.5°

<COD = 89°

mCD = <COD = 89°

Answer: 89°

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Andre notices that he is a little taller than Heather, who described her height as h is greater than 150 and h is less than 160

Nat2105 [25]

Answer:

a> h
a<164

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.

<em>Andre notices that he is a little taller than Lin, who described her height as h > and 150 h < 160 but andre is also shorter than their math teacher who is 164 centimeters tall. select the two inequalities that describe andress height</em>

Please have a look at the attached photo.

My answer:

Math teacher's height: 164 cm

Let Andre height is :a

We have Heather height: h

<=> h > and 150 h < 160

<=> 150 < h < 160

=> two inequalities that describe Andres height

a> h
a<164

Hope it will find you well

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2 years ago

using the pythagorean theorem, find the length of a leg of a right triangle if the other leg is 8 feet long and the hypotenuse i

8_murik_8 [283]

Phthagorean theorme is
a^2+b^2=c^2
where you have a right triangle and c =hypotonuse( normally the longest side, and opposite of right angle)
a and b are the legs

so we are given
one leg=8
hypotonues=10
subsitute
leg=a or b so just subsitute for one
subsitutt for b
a^2+8^2=10^2
expand
8^2=64
10^2=100
a^2+64=100
subtract 64 from both sides
a^2=36
square root both sides
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2 years ago

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liraira [26]

Answer:

Step-by-step explanation:

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2 years ago

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andreyandreev [35.5K]

14. (2x - 1)(x + 7) = 0

Using the zero factor property, we know that either the first or second terms (or both) must be equal to 0 if their product is 0. We can set each term equal to 0 to find the solutions:

2x - 1 = 0
2x = 1
x = 1/2

x + 7 = 0
x = -7

15. $x^{2} +3x=10$

To solve this equation, you first need to set it equal to 0:

$x^{2} +3x=10 \\ x^{2} +3x-10 = 0$

Next, it can be factored:

$x^{2} +3x-10 = 0 \\ (x+5)(x-2)=0$

Finally, we can solve just like we did above:

x + 5 = 0
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16. $4x^2=100$

First, you can simplify by dividing each side by 4:

$4x^2=100 \\ x^2=25$

Now, set the equation equal to 0:

$x^2=25 \\ x^2-25=0$

Next, factor:

$x^2-25=0 \\ (x+5)(x-5)=0$

Finally, find the solutions:

x + 5 = 0
x = -5

x - 5 = 0
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2 years ago

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Eva8 [605]

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