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umka2103 [35]
3 years ago
7

Rounding or compatible numbers to estimate de sum 222+203

Mathematics
1 answer:
yKpoI14uk [10]3 years ago
7 0
225 what are you in kindergarten use a calculator
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Harper is knitting a scarf for her cousin's birthday. She plans to knit every night, making the scarf 5 centimeters longer each
MissTica

The equation that shows the relationship between x and y is:

y = 5x

A linear equation is in the form:

y = mx + b

where m is the rate of change and b is the initial value of y, y, x are variables.

Let x represent the number of nights knitting and y represent the length of the scarf.

The equation that shows the relationship between x and y is:

y = 5x

Find out more at: brainly.com/question/13911928

8 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
What is the vertex for this function? y = 3x^2 + 12x + 5
xz_007 [3.2K]
That’s weird, it should be (-2,-7). Try (-2,7)
8 0
3 years ago
How to solve 7x+(-3)=18​
liq [111]

Answer:

x=3

Step-by-step explanation:

7x(-3)=18

add 3 to both sides

7x=21

divide by 7 on both sides

x=3

8 0
2 years ago
Read 2 more answers
What is 29.37 rounded to the nearest whole number
horsena [70]

Answer:

29

Step-by-step explanation:

Because if it was 5 or higher in front round up to 30 but because it's lower than 5 it's still 29.

7 0
2 years ago
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