As we know,
So, we can infer that :
Now, let's calculate the mass of gases in each case :
<h3>Case A : Hydrogen ~</h3>
or
<h3>Case B : Helium ~ </h3>
or
<h3>Case C : Nitrogen ~ </h3>
or
So, the arrangement of masses from least to greatest is :
- (1.) Hydrogen < (2.) Helium < (3.) Nitrogen
The right answer is:
<em>area B = area C</em>
We can solve this problem by using Kepler's laws of planetary motion. There are three Kepler's laws. In this exercise, we need to use the second law. According to this law,<em> a line segment joining a planet and the sun sweeps out equals areas during equals intervals of time. </em>So, a certain planet sweeps out an <em>area B </em>from the point <em>P3 </em>to <em>P4</em> in an interval of time <em>t. </em>On the other hand, for the same interval of time <em>t, </em>the planet sweeps out an <em>area C </em>from point <em>P4</em> to <em>P5, </em>that is equal to the previous area according to second kepler's law.
I believe it is D. hope this helps
You have a bucket 1 gallon big.
To mix cleaner and water you need to divide the bucket's capacity into 4.
It's easy in this case as gallon is divided into quarts (1 gallon is equal to 4 quarts).
<span>Since one part will be a window cleaner, it means that you will need to use </span>1 quart <span>of the cleaner. </span>
