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3 years ago

How much does 1521ml equal in deciliter?

1 answer:

4 0

1,521 millileters is equal to 15.21 deciliters.

In a deciliter, there are 100 milliliters. So, for this problem you would divide 1,521 by 100 to find the equality of milliliters to decimeters. Solving this, would give you 15.21 decimeters.

I hope this helps!!

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What is the product of (3a 2)(4a2 Ă˘â‚¬"" 2a 9)? 12a3 Ă˘Ââ€™ 2a 18 12a3 6a 9 12a3 Ă˘Ââ€™ 6a2 23a 18 12a3 2a2 23a 18.

Kay [80]

The product of $(3a + 2)(4a^2 - 2a + 9)$ will be $12a^3 + 2a^2 + 23a + 18.$

Given expression,

$(3a + 2)(4a^2 - 2a + 9).$

We have to find the product of $(3a + 2)(4a^2 - 2a + 9).$

Now using distributive property, we get

$3a(4a^2) - 3a(2a) + 3a(9) + 2(4a^2) - 2(2a) + 2(9)$

$12a^3 - 6a^2 + 27a + 8a^2 - 4a + 18$

$12a^3 + 2a^2 + 23a + 18$

Hence the product of $(3a + 2)(4a2 - 2a + 9)$ is $12a^3 + 2a^2 + 23a + 18.$

Thus the correct option is (D). $12a^3 + 2a^2 + 23a + 18.$

For more details on distributive property follow the link:

brainly.com/question/13130806

7 0

3 years ago

The box plots compare the weekly earnings of two groups of salespeople from different clothing stores. Find and compare the IQRs

jeka57 [31]

Answer:

Group A, IQR = 700

GROUP B, IQR =.450

Group A's IQR is greater

The values in the middle 50%.of Group A are more spread out Than those of Group B.

Step-by-step explanation:

Data for.each group :

The IQR = Q3 - Q1

From the boxplot :

Group A:

Q1 = 1100 ; Q3 = 1800

IQR = 1800 - 1100 = 700

Group B:

Q1 = 1400; Q3 = 1850

IQR = 1850 - 1400 = 450

Greater IQR = Group A

The values in the middle 50%.of Group A are more spread out Than those of Group B.

8 0

3 years ago

Suppose you are the manager of a firm the accounting department has provided cost estimates in the sales department sales estima

wlad13 [49]

Answer:

gfcfg

Step-by-step explanation:

8 0

4 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: