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Tema [17]
3 years ago
12

∆ABC rotates around point D to create ∆A′B′C′.

Mathematics
2 answers:
goldenfox [79]3 years ago
5 0

Answer:

A‘=(4,1)

A“=(11,8)

Step-by-step explanation:

A‘=(4,1)

A“=(11,8)

prohojiy [21]3 years ago
4 0

Answer:

The coordinates of A' are (4,1). Therefore the coordinates of A'' are (11,2).

Step-by-step explanation:

From the figure it is clear that the coordinates of triangle ABC are A(4,9), B(4,6) and C(2,6).

The ∆ABC rotates around point D to create ∆A′B′C′. The vertices of image are  B'(4,4) and C'(6,4).

From the figure it is clear that ∆ABC rotates 180° around point D to create ∆A′B′C′.

(x,y)\rightarrow (-x+8,-y+10)

The coordinates of A' are

A(4,9)\rightarrow A'(-4+8,-9+10)=A'(4,1)

The coordinates of A' are (4,1).

If ∆A′B′C′ rotates 90° counterclockwise around point E(7, 5) to form triangle ∆A″B″C″, then

(x,y)\rightarrow (-y+12,x-2)

The coordinates of A'' are

A'(4,1)\rightarrow A''(-1+12,4-2)=A''(11,2)

Therefore the coordinates of A'' are (11,2).

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