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3 years ago

Please help me with this

Mathematics

1 answer:

ElenaW [278]3 years ago

5 0

Answer:

SAS is the answer ...........

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I swear this is my last i-ready question lol

drek231 [11]

The area is 49 hopefully this is right have a nice day

3 0

3 years ago

Read 2 more answers

Marianne buys 16 bags of potting soil which come in 5/8 pound bags. This equals to 10 pounds of potting soil. Her father calls a

Ann [662]

Answer:

5 bags

Step-by-step explanation:

Given Marianne buys 16 bags of potting soil which come in 5/8 pound bags

The above provides 10pounds of potting soil already

Now her father says he needs 13 pounds So Marianne should get an extra of 13 - 10 =3 pounds of potting soil

We know that 1 bag contains 5/8 pounds of potting soil

x bags contain 3 pounds of potting soil

On cross multiplication we get

$\frac{5x}{8}=3$

x = $\frac{24}{5}$

since x is an integer x = 5 bags

Note that an extra amount of soil will be remained unused

8 0

3 years ago

What is the antiderivative of sin^2(x)cos^2(x)?

marin [14]

Answer:

$\frac{x}{8}-\frac{\sin(4x)}{32}+C$

Step-by-step explanation:

[Most of the work here comes from manipulating the trig to make the term (integrand) integrable.]

Recall that we can express the squared trig functions in terms of cos(2x). That is,

$\cos(2x)=2\cos^2x-1 \\ \cos(2x)=1 - 2\sin^2x.$

And so inverting these,

$\cos^2x=\frac{1}{2} (1+\cos2x) \\ \sin^2x=\frac{1}{2} (1-\cos2x)$ .

Multiply them together to obtain an equivalent expression for sin^2(x)cos^2(x) in terms of cos(2x).

$\sin^2x \cdot \cos^2x =\frac{1}{2} (1-\cos2x) \cdot \frac{1}{2} (1+\cos2x) = \frac{1}{4}(1-\cos^2(2x)).$

Notice we have cos^2(2x) in the integrand now. We've made it worse! Let's try plugging back in to the first identity for cos^2(2x).

$\cos(2x)=2\cos^2x-1 \Rightarrow \cos(4x)=2\cos^2(2x)-1 \Rightarrow \cos^2(2x) = \frac{1}{2}(1+\cos(4x))$

So then,

$\sin^2x \cdot \cos^2x = \frac{1}{4}(1-\cos^2(2x)) = \frac{1}{4}(1-\frac{1}{2}(1+\cos(4x))) = \frac{1}{4}(1-\frac{1}{2}-\frac{1}{2}\cos(4x))=\frac{1}{8}(1-\cos(4x)).$

This is now integrable (phew),

$\int \sin^2x\cos^2x \ dx = \int \frac{1}{8}(1-\cos(4x)) \ dx = \frac{1}{8} \int (1-\cos(4x)) \ dx = \frac{1}{8}(x-\frac{1}{4}\sin(4x))+C.$

7 0

3 years ago

A rectangle is 15m longer than it is wide. Its perimeter is 72m. Find its length and width.

Dahasolnce [82]

L 6 w 8 is the right answer to the question

6 0

2 years ago

Someone please help me out with this, thank you!

zaharov [31]

Answer:

(2,-2)

Step-by-step explanation:

the x-intercept is 2

and y-intercept is-2

x-intercept is when you have a number comma 0 e.g 3,0. 2,0

y-intercept is when u have 0 comma a number e.g 0,2 0,-5

3 0

3 years ago