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Ronch [10]
3 years ago
14

Find the average rate of change of a function that contains the points

Mathematics
2 answers:
ELEN [110]3 years ago
8 0

Answer:

1 / 2

Step-by-step explanation:

The average rate of change is the same as the slope.

Slope formula: (y₂ - y₁) / (x₂ - x₁)

= (5 - 3) / (2 - (-2))

= 2 / 4

= 1 / 2

Allisa [31]3 years ago
5 0

Answer:

1/2

Step-by-step explanation:

The rate of change is found by

y2-y1

---------

x2-x1

5-3

----------

2- -2

2/4

1/2

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Verdich [7]

Answer:

The answer is = 52

Step-by-step explanation:

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Christina can paint a chair in
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Answer:

<em>2</em>

Step-by-step explanation:

<em>I think because I had the same kind of question and the answer was 2 </em><em>,</em>

<em>hopefu</em><em>lly</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>u</em><em /><em>☺️</em>

6 0
3 years ago
A book store sells a textbook for $150. If the textbook is on sale with 12% off, and there is a sales tax of 8.25% added to the
Yuri [45]

The textbook is $150 originally, so to find the price of the textbook on sale, multiply the original price by 12% (0.12). Then subtract 12% of 150 from 150.

  • 150 * 0.12 = 18

Subtract 18 from 150.

  • 150 - 18 = 132

Multiply the price of the textbook on sale by the sales tax of 8.25% (0.0825). Then add the tax price onto the sale price of the textbook.

  • 132 * 0.0825 = 10.89

Add 10.89 to 132.

  • 132 + 10.89 = 142.89

The final price of the textbook is $142.89.

4 0
3 years ago
What is the inverse of the function g(x)=<br> -3(x + 6)?<br> g-1(x) =
Elanso [62]
Here’s the answer. See pictures.

3 0
3 years ago
Refer to the previous exercise. The researchers wanted a sufficiently large sample to be able to estimate the probability of pre
Maru [420]

Answer:

<em>The large  sample n = 117.07</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the estimate error (M.E) = 0.08

The proportion (p) = 0.75

q =1-p = 1- 0.75 =0.25

Level of significance = 0.05

Z₀.₀₅ = 1.96≅ 2

<u><em>Step(ii):-</em></u>

The Marginal error is determined by

M.E = \frac{Z_{0.05} \sqrt{p(1-p)}  }{\sqrt{n} }

0.08 = \frac{2 X \sqrt{0.75(1-0.75)}  }{\sqrt{n} }

Cross multiplication , we get

\sqrt{n}  = \frac{2 X \sqrt{0.75(1-0.75)}  }{0.08 }

√n = \frac{2 X0.4330}{0.08} = 10.825

squaring on both sides , we get

n = 117.07

<u><em>Final answer:-</em></u>

<em>The large  sample n = 117.07</em>

6 0
2 years ago
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