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____ [38]
2 years ago
13

I need help with this

Mathematics
2 answers:
HACTEHA [7]2 years ago
8 0

Answer:

1. measure of angle E is 90 degrees

2. Measure of angle F + measure of angle G is 90 degrees

Step-by-step explanation:

Angle E is 90 degrees because it is marked as a right angle (the square)

A triangle has 180 degrees so if E is 90 degrees then the other 2 also have to equal 90 degrees

Crazy boy [7]2 years ago
8 0
Yeah what he said^ hooray
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-10x-3-2.5x+20=67 solve equation
dlinn [17]

Answer:

x = -4

Step-by-step explanation:

combine like terms

-10x - 3 - 2.5x + 20 = 67

-12.5x + 17 = 67

subtract 17 from both sides of the equal sign

-12.5x = 50

divide -12.5 from both sides of the equal sign

x = -4

4 0
3 years ago
a baseball league finds the speeds of pitches are normally distributed, with a mean of 89 mph and a standard deviation of 2.4 mp
olya-2409 [2.1K]

Answer:

-1.58

Step-by-step explanation:

We have that the mean (m) is equal to 89 and the standard deviation (sd) 2.4

They ask us for P (x <85.2)

For this, the first thing is to calculate z, which is given by the following equation:

z = (x - m) / (sd)

We have all these values, replacing we have:

z = (85.2 - 89) / (2.4)

z = -1.58

8 0
3 years ago
If you want to buy an item in a store that costs $15 and is on sale for 15% off, then how much would the item actually cost you
Sholpan [36]
You would have to suck a ban
5 0
3 years ago
Read 2 more answers
Chad has a rope that is 20 yards long. How many pieces of rope measuring 4/7 of a yard can he divide his rope into?
Sunny_sXe [5.5K]

Answer:

35\ pieces

Step-by-step explanation:

we know that

To find the number of pieces of rope 4/7 of a yard, divide the total length of the rope by 4/7

we have that

The total length of the rope is 20 yards

so

\frac{20}{(4/7)}=\frac{20*7}{4}=35\ pieces

4 0
3 years ago
Read 2 more answers
In a random sample of cars driven at low altitudes, of them exceeded a standard of grams of particulate pollution per gallon of
Orlov [11]

Complete question is;

In a random sample of 370 cars driven at low altitudes, 43 of them exceeded a standard of 10 grams of particulate pollution per gallon of fuel consumed. In an independent random sample of 80 cars driven at high altitudes, 23 of them exceeded the standard. Can you conclude that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard at an level of significance? Group of answer choices

Answer:

Yes we can conclude that there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard (P-value = 0.00005).

Step-by-step explanation:

This is a hypothesis test for the difference between the proportions.

The claim is that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

Then, the null and alternative hypothesis are:

H0 ; π1 - π2 = 0

H1 ; π1 - π2 < 0

The significance level would be established in 0.01.

The random sample 1 (low altitudes), of size n1 = 370 has a proportion of;

p1 = x1/n1

p1 = 43/370

p1 = 0.116

The random sample 2 (high altitudes), of size n2 = 80 has a proportion of;

p2 = x2/n2

p2 = 23/80

p2 = 0.288

The difference between proportions is pd = (p1-p2);

pd = p1 - p2 = 0.116 - 0.288

pd = -0.171

The pooled proportion, we need to calculate the standard error, is:

p = (x1 + x2)/(n1 + n2)

p = (43 + 23)/(370 + 80)

p = 66/450

p = 0.147

The estimated standard error of the difference between means is computed using the formula:

S_(p1-p2) = √[((p(1 - p)/n1) + ((p(1 - p)/n2)]

1 - p = 1 - 0.147 = 0.853

Thus;

S_(p1-p2) = √[((0.147 × 0.853)/370) + ((0.147 × 0.853)/80)]

S_(p1-p2) = 0.044

Now, we can use the formula for z-statistics as;

z = (pd - (π1 - π2))/S_(p1-p2)

z = (-0.171 - 0)/0.044

z = -3.89

Using z-distribution table, we have the p-value = 0.00005

Since the P-value of (0.00005) is smaller than the significance level (0.01), then the effect is significant.

We conclude that The null hypothesis is rejected.

Thus, there is enough evidence to support the claim that the proportion of high-altitude vehicles exceeding the standard is greater than the proportion of low-altitude vehicles exceeding the standard.

6 0
2 years ago
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