The area of a rhombus with length of diagonal as 24 inches and 36 inches is 432 in²
<h3>Rhombus</h3>
Rhombus is a quadrilateral with two pairs of opposite and equal parallel sides. All the sides of a rhombus are equal and the diagonals bisect each other at 90 degrees.
The area (A) of a rhombus is given by:
where p, q are the length of the diagonals.
Given that:
- p = 24 in, q = 36 in, hence:
- A = (24 * 36) / 2
- A = 432 in²
The area of a rhombus with length of diagonal as 24 inches and 36 inches is 432 in²
Find out more on Rhombus at: brainly.com/question/88523
Answer:
Alright, sweetheart. Your answer is C. I'm gonna tell you how so you can do it on your own from now on.
Step-by-step explanation:
Slope is the number of times you go up over the number of times you go over. This slope is a positive slope because up and right are both positive directions. Look at where the line crosses over on -3. Go up till you see where the line intersects again and then count the number of spaces you have to go over to get to the next intersection. I hope this helps.
Answer:
number 8 is the product o hope i got it in time for you
Answer:
60
Step-by-step explanation:
80/100 times 75 and you will get 60
Answer:
The height of the cone is 5.09 inches
Step-by-step explanation:
Given:
The volume of the cone = 12 cubic inches
The diameter of the cone = 3 inches
To Find :
The height of the cone = ?
Solution:
We know that the volume of the cone is
Volume = 
where
r is the radius of the cone
h is the height of the cone
Now substituting the given values
h = 5.09 inches
