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3 years ago

Need help, I don’t understand

Mathematics

1 answer:

Ksivusya [100]3 years ago

4 0

34 Degrees because -7 - 27 = -34

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3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie

allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

$\displaystyle \tan 53^\circ=\frac{150-x}{h}$

$\displaystyle \tan 48^\circ=\frac{x}{h}$

From the last equation:

$x=h.\tan 48^\circ$

Substituting into the first equation:

$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

Rearranging:

$\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}$

Solving for h:

$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0

2 years ago

A flagpole is at the top of a building. 300 feet from the base of the building, the angle of elevation of the top of the pole is

Grace [21]

Answer: We can use tangent here to find the length of the flagpole

First, find the length of the building + the flag pole

tan 32 = x/300

x=300tan32=187.460805573

(length of building + flagpole)

find length of building

tan 30 = x/300

x=173.205080757

subtract

187.460805573-173.205080757=14.255724816

round, length of flagpole = 14 feet

7 0

2 years ago

Find the distance between the pair of points.

SVEN [57.7K]

Answer:

Distance is $\sqrt{290}$ units

Step-by-step explanation:

Use the distance formula which is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ where $d$ is the distance between points $(x_1,y_1)$ and $(x_2,y_2)$

We are given that $(x_1,y_1)$ is $(-6,-23)$ and $(x_2,y_2)$ is $(-23,-24)$ , therefore the distance between the two points is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}$

$d=\sqrt{(-23+6))^2+(-24+23))^2}$

$d=\sqrt{(-17)^2+(-1)^2}$

$d=\sqrt{289+1}$

$d=\sqrt{290}$

Therefore, the distance between $(-6,-23)$ and $(-23,-24)$ is $\sqrt{290}$ units.

3 0

2 years ago

James walked 548 yards. How many miles has he walked ?

Lana71 [14]

One yard is 0.0005 miles,
548 * 0.0005 = 0.274,
So the answer is 0.274 miles.

Hope this helps.

3 0

2 years ago

Read 2 more answers

What is the value of x?

N76 [4]

Answer:

i think it would be 55

Step-by-step explanation:

8 0

2 years ago