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podryga [215]
3 years ago
14

Make m the subject in the relation

d="TexFormula1" title="2m - x + 3y \h = 2y \p" alt="2m - x + 3y \h = 2y \p" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
il63 [147K]3 years ago
7 0

Answer:

m = \frac{-y+x}{2}

Step-by-step explanation:

2m - x + 3y = 2y

Take -x and +3y on the other side of the equal to sign:

2m = 2y +x-3y

Now solve for y:

2m = -y +x

Take 2 one the other side of the equation:

m = \frac{-y +x}{2}

Hope this helps :)

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3 0
3 years ago
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lisov135 [29]

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Explanation:

It is given that DBCA is a quadrilateral. Since it is a quadrilateral it means the have 4 vertices and 4 angles D, B,C,A.

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If the quadrilateral name is DBCA it means the sides are DB, BC, CA and AD as shown in the figure.

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4 years ago
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