Find 5 points that satisfy the equation y= 12+2x

1 answer:

8 0

We start by finding the intercept of the line: what does y equal when x=0? and what does x equal when y=0?
• intercept in x
y = 12 + 2x
0 = 12 + 2x
-12 = 2x
-6 = x
• intercept in y
y = 12 + 2x
y = 12 + 2(0)
y = 12 + 0
y = 12
Now we find three more points giving y a value and finding x
y = 12 + 2x
2 = 12 + 2x
2-12 = 2x
-10 = 2x
-5 = x

y = 12 + 2x
6 = 12 + 2x
6 - 12 = 2x
-6 = 2x
-3 = x

y = 12 + 2x
14 = 12 + 2x
14 - 12 = 2x
2 = 2x
1 = x

Notice how I gave y even numbers as values since we would have to divide with 2 at the end.

Sol. {(-6,0)(0,12)(-5,2)(-3,6)(1,14)}

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Answer:

Step-by-step explanation:

Mistakes: The student did not distribute the 3 into 2, and the student did not distribute the 6 into negative 2. The student also left out the negative 2x in the first half of the equation.

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