All categories

3 years ago

Perpendicular lines are always, sometimes , never coplanar

Mathematics

2 answers:

daser333 [38]3 years ago

8 0

They are always on a coplanar

stiv31 [10]3 years ago

3 0

Answer:

Perpendicular lines are always coplanar.

Step-by-step explanation:

Coplanar lines are lines drawn on the same plane. So whenever you have

perpendicular lines (i.e lines at right angle to each other), they are always coplanar. This is because they are drawn on the same plane.

You might be interested in

Evaluate the following expression: 62 − 7(8 + 6 − 32)

Alex Ar [27]

Answer:

188

Step-by-step explanation:

Step 1: Distribute

62 − 7(8 + 6 − 32)

62 + (-7 * 8) + (-7 * 6) + (-7 * -32)

62 + (-56) + (-42) + (224)

Step 2: Combine the first two numbers

(62 - 56) - 42 + 224

6 - 42 + 224

Step 3: Combine the next two number

(6 - 42) + 224

-36 + 224

Step 4: Combine the last two number

-36 + 224

188

Answer: 188

3 0

3 years ago

The circumference of a circle

Dmitry_Shevchenko [17]

Use the formula C = pi * d

8 0

4 years ago

Out of 22 players in a team, 10 of them have an average height of 1.50m while another 10 have an average height of 1.48m. The re

Sonja [21]

Answer:

1.5 meters

Step-by-step explanation:

We know that the sum of all of the data in a set = average * number of data.

Therefore, the sum of the first 10 is 1.5 * 10 = 15 meters, the sum of the second 10 is 1.48 * 10 = 14.8 meters and the sum of the last 2 is 1.6 * 2 = 3.2 meters for a total of 15 + 14.8 + 3.2 = 33 meters. This means that the mean is 33 / 22 = 1.5 meters.

6 0

3 years ago

Read 2 more answers

A textbook search committee is considering

lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

Step-by-step explanation:

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

Repetition is Allowed: such as the lock above. It could be "333".

No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

$nC_r= \frac{n!}{r! (n-r)!}$ , where n is the number of things to choose from, and we choose r of them, no repetitions, order matters. Here , n=13 , r=3.

⇒ $13C_3 = \frac{13!}{3!(13-3)!}$

⇒ $13C_3 = \frac{13!}{3!(10)!}$

⇒ $13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}$

⇒ $13C_3 = 13(2)(11)$

⇒ $13 C_3 = 286$

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0

3 years ago

The radioactive isotope radium has a half-life of 1,600 years. The mass of a 100-gram sample of radium will be______ grams after

Olenka [21]

To solve this we are going to use the half life equation $N(t)=N_{0} e^{( \frac{-0.693t}{t _{1/2} }) }$
Where:
$N_{0}$ is the initial sample
$t$ is the time in years
$t_{1/2}$ is the half life of the substance
$N(t)$ is the remainder quantity after $t$ years

From the problem we know that:
$N_{0} =100$
$t=200$
$t_{1/2} =1600$

Lets replace those values in our equation to find $N(t)$ :
$N(200) =100e^{( \frac{(-0.693)(200)}{1600}) }$
$N(200)=100e^{( \frac{-138.6}{1600} )}$
$N(200)=100e^{-0.086625}$
$N(200)=91.7$

We can conclude that after 1600 years of radioactive decay, the mass of the 100-gram sample will be 91.7 grams.

8 0

3 years ago