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Sidana [21]
3 years ago
13

Help asap do all show work

Mathematics
1 answer:
love history [14]3 years ago
6 0

y=-x

slope for perp line = 1

2y=-x+6

y=-1/2x +3

slope for perp line = 2

15.

i don’t wanna do all sorry it’s a lot of work so i’ll tell u how to do it instead. first write it in slope intercept form which is

y-y1=m(x-x1)

it’s parallel which means it shares the same slope. if it’s perpendicular it would be opposite reciprocals so for -3/2 the perp slope would be 2/3.

the line is

y+1=3/4(x-4)

we distribute the 3/4 so it’s now

y+1=3/4x-3

then we subtract the 1

y=3/4x-4 is the equation boom done

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Aleks [24]
The answer should be 142.50 square units. The unshaded part is is a triangle and so it’s bh/2 so 19x5/2 which is 95/2 or 47.5. Then the whole entire rectangle is 19x10 so 190. 190-47.5= the shaded region
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3 years ago
Find the dimensions and the perimeter of side AEHD.Select all the correct answers. A rectangular prism is 7 centimeters long, 5
borishaifa [10]

Answer:

Step-by-step explanation:

2 x w x l + 2 x l x h + 2 x h x w

* is times  2*5*7+2*7*4+2*4*5 =

= 70+56+40=166 cm

Hope it helps

4 0
3 years ago
There are 100 tiles that were purchased to raise money for a new playground. The tiles will be laid along a walkway. Each tile i
UNO [17]

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7 0
3 years ago
30 POINTS AVAILABLE
kherson [118]

Answer:

\large\boxed{(x-2)^2+(y-1)^2=34}

Step-by-step explanation:

The equation of a circle in standard form:

(x-h)^2+(y-k)^2=r^2

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)

Substitute:

h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute the coordinates of the points (2, 1) and (5, -4):

r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}

Finally we have:

(x-2)^2+(y-1)^2=(\sqrt{34})^2

3 0
4 years ago
Make h the subject of the formula<br><br> t=gh/10
Lera25 [3.4K]
Here, t = gh/10
gh = 10t
h = 10t/g

In short, Your Answer would be 10t / g

Hope this helps!
7 0
3 years ago
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