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3 years ago

Please help I’ll give brainliest

Mathematics

2 answers:

il63 [147K]3 years ago

6 0

Answer:

2 is the base

Step-by-step explanation:

2^3

2 is the base and 3 is the exponent

sergeinik [125]3 years ago

3 0

The answer is the base is 2 (first option)

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You invest $1,900 At 4% and it’s compounded semi annually for 3 years. How much will your $1,900 Be worth in 3 years?

blondinia [14]

Investment we not would be worth $2139.71

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3 years ago

Mr. Robinson washed 2/5 of his laundry. His son washed 1/4 of his laundry. Who washed more? How much laundry still need to be wa

Eddi Din [679]

Answer:

Mr.Robinson; 27/40 i think.

Step-by-step explanation: To begin solving you have to make both of the denominators the same by multiplying 2/5 by 4 and 1/4 by 5 giving you 8/20 and 5/20. From there i'm pretty sure you just add the two fractions to get 13/40 leaving 27/40 to be washed.

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3 years ago

PLEASE HELP LOOK AT THE PICTURE I NEED HELP NOWWWW!!!! WILL GIVE 20 POINTSSSSSS!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Verdich [7]

Answer:

A. 35

Step-by-step explanation:

√35 = 5.9160797830996160425673282915616170484155012307943403228797196691

6 0

3 years ago

Read 2 more answers

X to the power of 2 subtract 3x for x=4

Helen [10]

First, X^2 while x is 4 =4^2, which is 4x4, which is 16
3X while x is 4 is 12. 16-12=4. So the answer is 4

6 0

3 years ago

What would y=x^2 +x+ 2 be in vertex form

balu736 [363]

Answer:

$y = (x + \frac{1}{2} )^{2} + \frac{7}{4}$

Step-by-step explanation:

$y = {x}^{2} + x + 2$

We can covert the standard form into the vertex form by either using the formula, completing the square or with calculus.

$y = a(x - h)^{2} + k$

The following equation above is the vertex form of Quadratic Function.

Vertex — Formula

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

We substitute the value of these terms from the standard form.

$y = a {x}^{2} + bx + c$

$h = - \frac{1}{2(1)} \\ h = - \frac{ 1}{2}$

Our h is - 1/2

$k = \frac{4(1)(2) - ( {1})^{2} }{4(1)} \\ k = \frac{8 - 1}{4} \\ k = \frac{7}{4}$

Our k is 7/4.

Vertex — Calculus

We can use differential or derivative to find the vertex as well.

$f(x) = a {x}^{n}$

Therefore our derivative of f(x) —

$f'(x) = n \times a {x}^{n - 1}$

From the standard form of the given equation.

$y = {x}^{2} + x + 2$

Differentiate the following equation. We can use the dy/dx symbol instead of f'(x) or y'

$f'(x) = (2 \times 1 {x}^{2 - 1} ) + (1 \times {x}^{1 - 1} ) + 0$

Any constants that are differentiated will automatically become 0.

$f'(x) = 2 {x}+ 1$

Then we substitute f'(x) = 0

$0 =2x + 1 \\ 2x + 1 = 0 \\ 2x = - 1 \\x = - \frac{1}{2}$

Because x = h. Therefore, h = - 1/2

Then substitute x = -1/2 in the function (not differentiated function)

$y = {x}^{2} + x + 2$

$y = ( - \frac{1}{2} )^{2} + ( - \frac{1}{2} ) + 2 \\ y = \frac{1}{4} - \frac{1}{2} + 2 \\ y = \frac{1}{4} - \frac{2}{4} + \frac{8}{4} \\ y = \frac{7}{4}$

Because y = k. Our k is 7/4.

From the vertex form, our vertex is at (h,k)

Therefore, substitute h = -1/2 and k = 7/4 in the equation.

$y = a {(x - h)}^{2} + k \\ y = (x - ( - \frac{1}{2} ))^{2} + \frac{7}{4} \\ y = (x + \frac{1}{2} )^{2} + \frac{7}{4}$

7 0

3 years ago