Given quadrilateral ABCD ~ quadrilateral JKLM and AD = 14, JM = 6, and KL = 9, what is BC?
1 answer:
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Answer:
For figure 1: The equation of a line is y=1
For figure 2: The equation of a line is y=(-4)x+1
For figure 3:The equation of a line is y=
Step-by-step explanation:
The equation of line slope-intercept form is given by y=mx+c
Where m is the slope of the line and c is the y-intercept.
For figure 1:
Here, Line is parallel to x-axis
Hence, Slope m=0
Also, Line passing to y axis at (0,1)
Y-intercept is c=1
Therefore,
The equation of line is
y=0x+1
y=1
For figure 2:
Figure show a line passing through point (1,-3) and (-1,5)
The slope of the line is given by m=
Using given points to find out the slope of a line
m=
m=
m=
m=(-4)
Also, Line is intersecting y-axis at (0,1)
Hence, c=1
We can write the equation of line as
y=mx+c
y=(-4)x+1
Thus, The correct option is D). y=(-4)x+1
For figure 3:
From the figure, a line is passing through points (-2,0) and (0,5)
The slope of the line is given by m=
Using given points to find out the slope of a line
m=
m=
m=
Also, Line is intersecting y-axis at (0,5)
Hence, c=5
We can write the equation of line as
y=mx+c
y=