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Zolol [24]
3 years ago
8

Given quadrilateral ABCD ~ quadrilateral JKLM and AD = 14, JM = 6, and KL = 9, what is BC?

Mathematics
1 answer:
xeze [42]3 years ago
3 0
ABCD ; AD = 14 ; BC = ?
JKLM ; JM = 6 ; KL= 9

6/14 = 9/X
6X = 9*14
6X = 126
X = 126/6
X = 21

14/6 = 2 1/3
21/9 = 2 1/3

BC = 21

QUADRILATERAL ABCD IS 2 1/3 TIMES BIGGER THAN QUADRILATERAL JKLM
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12^13–12^12+12^11 is divisible by 7 and 19.
fiasKO [112]

Answer:

The statement is true

Step-by-step explanation:

The question is as following :

12^{13}-12^{12}+12^{11} is divisible by 7 and 19, true or false?

The given expression is 12^{13}-12^{12}+12^{11}

Take 12^{11} as a common

12^{13}-12^{12}+12^{11} = 12^{11}*(12^2-12^1+12^0)\\= 12^{11} *(144-12+1)\\=12^{11} * 133\\= 12^{11} * 7 * 19

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8 0
3 years ago
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cluponka [151]
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The answer is - 27
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