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3 years ago

What are the excluded values of x for 2-3x-28/х2-2x-35

Mathematics

2 answers:

JulsSmile [24]3 years ago

6 0

Answer:

Step-by-step explanation:

The excluded values are the values of x that make the denominator of the rational function equal to zero as this would make the function undefined.

Equate the denominator to zero and solve for x to obtain the values that x cannot be.

x² - 2x - 35 = 0

(x - 7)(x + 5) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 7 = 0 ⇒ x = 7

x + 5 = 0 ⇒ x = - 5

Excluded values of x are x = - 5, x = 7 → C

Lorico [155]3 years ago

3 0

I'm gonna have to say its c

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2 years ago

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Then our integral is:

$\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2} + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3} + (-1) - \frac{(-1)^2}{2} )$

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2 years ago

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